Skip to main content
class_is_disjoint_from_literals
regex_
automata
0.4.16
In regex_
automata::
meta::
prefix
regex_automata
::
meta
::
prefix
Function
class_
is_
disjoint_
from_
literals
Copy item path
Source
fn class_is_disjoint_from_literals(cls: &
Class
, literals: &[
Literal
]) ->
bool